52 lines
No EOL
1.6 KiB
Lua
52 lines
No EOL
1.6 KiB
Lua
-- meat-factory.lua
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MeatFactory = {}
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MeatFactory.__index = MeatFactory
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local Meat = require("meat")
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function MeatFactory:new(spawnRate, meatTypes, meatTable)
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local instance = setmetatable({}, MeatFactory)
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instance.spawnRate = spawnRate
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instance.meatTypes = meatTypes
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instance.meatTable = meatTable
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instance.spawnTimer = 0
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return instance
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end
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function MeatFactory:update(dt)
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self.spawnTimer = self.spawnTimer + dt
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if self.spawnTimer >= self.spawnRate then
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self:spawnMeat()
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self.spawnTimer = 0
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end
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end
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function MeatFactory:spawnMeat()
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local meatType = self.meatTypes[math.random(#self.meatTypes)]
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local meat = Meat:new()
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meat:loadImages() -- Load images for the meat
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meat.meatType = meatType
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meat.currentImage = meat.images[meatType]
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meat.value = self:getMeatValue(meatType)
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-- Set the x and y coordinates to be within the bounds of the meat table
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local meatTableX = (love.graphics.getWidth() - self.meatTable.image:getWidth()) / 2
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local meatTableY = (love.graphics.getHeight() - self.meatTable.image:getHeight()) / 2
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meat.x = meatTableX + (self.meatTable.image:getWidth() - meat.currentImage:getWidth()) - 15
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meat.y = meatTableY + (self.meatTable.image:getHeight() - meat.currentImage:getHeight()) - 30
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table.insert(instances.meats, meat)
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end
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function MeatFactory:getMeatValue(meatType)
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-- You can implement a logic to determine the value of the meat based on its type
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-- For example:
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if meatType == "chicken" then
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return 10
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elseif meatType == "cow" then
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return 20
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elseif meatType == "pig" then
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return 15
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end
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end
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return MeatFactory |